以题会友，哈哈O(∩_∩)O~

CCDDACACDB

要求给出证明过程。

？

第三题题目什么意思，你解释一下

对于这种题，我只能有一种回答

DCDDACACDB
从3 5入手很容易看出只能选DA
之后活用成立不成立的条件就好了

('A', 'C', 'D', 'D', 'A', 'D', 'A', 'C', 'D', 'B')
('C', 'C', 'D', 'D', 'A', 'C', 'A', 'C', 'D', 'B')
('C', 'C', 'D', 'D', 'A', 'D', 'A', 'C', 'D', 'B')
('D', 'C', 'D', 'D', 'A', 'C', 'A', 'C', 'D', 'B')

from itertools import product
answers = ['A', 'B', 'C', 'D']
all_possible_combinations = list(product(answers, repeat=10))
def check_conditions(combination):
if combination[1] == 'A' and combination[4] != 'C':
return False
if combination[1] == 'B' and combination[4] != 'D':
return False
if combination[1] == 'C' and combination[4] != 'A':
return False
if combination[1] == 'D' and combination[4] != 'B':
return False
if combination[2] == 'A':
if combination[5] != combination[2]:
return False
if combination[2] == 'B':
if combination[4] != combination[5]:
return False
if combination[2] == 'C':
if combination[3] != combination[4]:
return False
if combination[2] == 'D':
if combination[2] != combination[3]:
return False
if combination[3] == 'A':
index_a = answers.index(combination[2])
index_b = answers.index(combination[9])
if abs(index_a - index_b) != 1:
return False
if combination[3] == 'B':
index_a = answers.index(combination[5])
index_b = answers.index(combination[7])
if abs(index_a - index_b) != 1:
return False
if combination[3] == 'C':
index_a = answers.index(combination[0])
index_b = answers.index(combination[4])
if abs(index_a - index_b) != 1:
return False
if combination[3] == 'D':
index_a = answers.index(combination[1])
index_b = answers.index(combination[8])
if abs(index_a - index_b) != 1:
return False
if combination[4] == 'A':
if combination[4] != combination[6]:
return False
if combination[4] == 'B':
if combination[4] != combination[5]:
return False
if combination[4] == 'C':
if combination[4] != combination[3]:
return False
if combination[4] == 'D':
if combination[4] != combination[2]:
return False
if combination[5] == 'A':
if combination[9] != combination[1]:
return False
if combination[5] == 'B':
if combination[7] != combination[9]:
return False
if combination[5] == 'C':
if combination[5] != combination[7]:
return False
if combination[5] == 'D':
if combination[3] != combination[5]:
return False
answer_counts = {answer: combination.count(answer) for answer in answers}
least_selected = min(answer_counts, key=answer_counts.get)
if combination[6] == 'A' and least_selected != 'B':
return False
if combination[6] == 'B' and least_selected != 'A':
return False
if combination[6] == 'C' and least_selected != 'D':
return False
if combination[6] == 'D' and least_selected != 'C':
return False
most_selected = max(answer_counts, key=answer_counts.get)
if combination[7] == 'A':
for i in range(0, 9):
if combination[i] == most_selected:
if i == 2:
return False
if i == 4:
return False
if combination[7] == 'B':
for i in range(0, 9):
if combination[i] == most_selected:
if i == 0:
return False
if i == 2:
return False
if combination[7] == 'C':
for i in range(0, 9):
if combination[i] == most_selected:
if i == 4:
return False
if i == 6:
return False
if combination[7] == 'D':
for i in range(0, 9):
if combination[i] == most_selected:
if i == 6:
return False
if i == 8:
return False
x2 = answers.index(combination[1])
x4 = answers.index(combination[3])
x10 = answers.index(combination[9])
X = x2 - (x4 - x10)
if combination[8] == 'A':
if X != answers.index(combination[7]):
return False
if combination[8] == 'B':
if X != answers.index(combination[8]):
return False
if combination[8] == 'C':
if X != answers.index(combination[1]):
return False
if combination[8] == 'D':
if X != answers.index(combination[4]):
return False
frequency_difference = answer_counts[most_selected] - answer_counts[least_selected]
if combination[9] == 'A' and frequency_difference != 4:
return False
if combination[9] == 'B' and frequency_difference != 3:
return False
if combination[9] == 'C' and frequency_difference != 2:
return False
if combination[9] == 'D' and frequency_difference != 1:
return False
return True
for combination in all_possible_combinations:
if check_conditions(combination):
valid_answer = combination
print(valid_answer)

看不種題目，尤其是第九題，第二題的答案是英文，怎麼用減法？