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一个非常简单地if else结构+ 请大神帮忙+ 急!!!

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计算机课要编一个slot machine的程序
具体就是
如果三个数是7,那么赢1000;
如果三个数相同但不是7,那么赢500;
如果两个为7,一个为6,那么赢400;
除此之外,如果两个相同,那么赢100;
其他情况就打印 "YOU WON NOTHING."
我写了如下程序:
import java.lang.Math;
public class Assn1_2150130 {
public static void main(String[] args) {
// Generate three random signle-digit integar from 0-7.
int n1 = (int)(Math.random()*7);
int n2 = (int)(Math.random()*7);
int n3 = (int)(Math.random()*7);
System.out.println( n1 +" "+ n2 + " " + n3);
int winning=0;
String str = "NOTHING";
if (n1==n2 && n2==n3 && n3==7) // Print out the result that of winning $1000.
winning = 1000;
else if (n1==n2 && n2==n3 && n3!=7)
winning = 500;
else if (n3==n2 && n2==7 && n1==6)
winning = 400;
else if (n1==n3 && n3==7 && n2==6)
winning = 400;
else if (n1==n2 && n2==7 && n3==6)
winning = 400;
else if (n1==n2 && n2!=7 && n3==6)
winning = 100;
else if (n1==n2 && n2==7 && n3!=6)
winning = 100;
else if (n1==n2 && n2!=7 && n3!=6)
winning = 100;
else if (n2==n3 && n3!=7 && n1==6)
winning = 100;
else if (n2==n3 && n3==7 && n1!=6)
winning = 100;
else if (n2==n3 && n3!=7 && n1!=6)
winning = 100;
else if (n1==n3 && n3!=7 && n2==6)
winning = 100;
else if (n1==n3 && n3==7 && n2!=6)
winning = 100;
else if (n1==n3 && n3!=7 && n2!=6)
winning = 100;
//Print out the winning amount if there is any.
System.out.println("You won" + " " + winning + ".");
if (n1!=n2 && n2!=n3 && n1!= n3)
winning = 0;
System.out.println("You won NOTHING.");
}
}
本来也没想着用什么高级办法,结果到最后一步的时候不行。死活没法单独打印 "You won NOTHING."。实在想不出了,晚上就到交了,求救!


1楼2015-02-07 04:31回复