都来看一看，解一解啊。。。

x^2-2x+2=a 有a^2-2a-3＞0 (a-1)^2-4＞0 （x^2-2x+2-1）^2-4＞0 ((x-1)^2)^2-4＞0 剩下的....

(x²-2x+2)²-2(x²-2x+2)-3＞0
(x²-2x+2)²-2(x²-2x+2)-3=(x²-2x+2-3)(x²-2x+2+1)
=(x²-2x-1)(x²-2x+3)=[(x-1)²-2][(x-1)²+2]
=(x-1+√2)(x-1-√2)[(x-1)²+2]>0;
(x-1+√2)(x-1-√2)>0;
x>√2+1或x<1-√2;